If a 7.5 hp motor has a service factor of 1.20 and normally draws 17 amps, what is the maximum it can pull temporarily without damage?

To determine the maximum current a motor can temporarily pull without damage, you can use the service factor in conjunction with the normal amperage. The service factor indicates the extent to which a motor can operate beyond its rated capacity without sustaining damage for a limited time.

In this case, the motor has a service factor of 1.20 and normally draws 17 amps. To find the maximum amperage, you would multiply the normal current by the service factor:

Maximum Amperage = Normal Amperage × Service Factor

Substituting the given numbers:

Maximum Amperage = 17 amps × 1.20 = 20.4 amps

This value of 20.4 amps reflects the temporary overload capability of the motor while ensuring it remains safe from damage. Thus, the correct answer indicates the maximum temporary amperage based on the motor's rated service factor and normal operation. This calculation reinforces the importance of understanding service factors when evaluating motor capacity and operational limits.